Get Free NCERT Solutions for Class 10 Maths Chapter 6 Ex 6.6 PDF. Triangles Class 10 Maths NCERT Solutions are extremely helpful while doing your homework. Exercise 6.6 Class 10 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 6 Maths Class 10 Triangles Exercise 6.6 provided in NCERT TextBook.

**Topics and Sub Topics in Class 10 Maths Chapter 6 Triangles:**

Section Name | Topic Name |

6 | Triangles |

6.1 | Introduction |

6.2 | Similar Figures |

6.3 | Similarity Of Triangles |

6.4 | Criteria For Similarity Of Triangles |

6.5 | Areas Of Similar Triangles |

6.6 | Pythagoras Theorem |

6.7 | Summary |

- Triangles Class 10 Ex 6.1
- Triangles Class 10 Ex 6.2
- Triangles Class 10 Ex 6.3
- Triangles Class 10 Ex 6.4
- Triangles Class 10 Ex 6.5
- Triangles Class 10 Ex 6.6
- Extra Questions for Class 10 Maths Triangles

You can also download the free PDF of Ex 6.6 Class 10 Triangles NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation.

Board | CBSE |

Textbook | NCERT |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 6 |

Chapter Name | Triangles |

Exercise | Ex 6.6 |

Number of Questions Solved | 10 |

Category | NCERT Solutions |

## NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.6

NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex Ex 6.6 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6

Question 1.

In the given figure, PS is the bisector of ∠QPR of ∆PQR. Prove that

Solution:

Question 2.

In the given figure, D is a point on hypotenuse AC of ∆ABC, DM ⊥ BC and DN ⊥ AB. Prove that:

(i) DM^{2} = DN X MC

(ii) DN^{2} = DM X AN

Solution:

Download NCERT Solutions For Class 10 Maths Chapter 6 Triangles PDF

Question 3.

In the given figure, ABc is triangle in which ∠ABC > 90° and AD ⊥ CB produced. Prove that AC^{2} = AB^{2} + BC^{2} + 2BC X BD

Solution:

Question 4.

In the given figure, ABC is atriangle in which ∠ABC 90° and AD ⊥ CB. Prove that AC^{2} = AB^{2} + BC^{2} – 2BC X BD

Solution:

Question 5.

In the given figure, Ad is a median of a triangle ABC and AM ⊥ BC. Prove that

Solution:

Question 6.

Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of the squares of its sides.

Solution:

Question 7.

In the given figure, two chords AB and CD intersect each other at the point P. Prove that:

(i) ∆APC ~∆DPB

(ii) AP X PB = CP X DP

Solution:

Question 8.

In the given figure, two chords Ab and CD of a circle intersect each other at the point P (when produced) outside the circle. Prove that:

(i) ∆PAC ~ ∆PDB

(ii)PA X PB = PC X PD

Solution:

Question 9.

In the given figure, D is a point on side BC of ∆ABC, such that Prove that AD is the bisector of ∆BAC.

Solution:

Question 10.

Nazima is fly fishing in a stream. The trip of her fishing rod is 1.8m above the surface of the water and the fly at the end of the string rests on the water 3.6m away and 2.4 m from a point directly under the trip of the rod. Assuming that her string (from the trip of the rod to the fly) is that, how much string does she have out (see the figure)? If she pills in the string at the rate of 5 cm per second, what will be the horizontal distance of the fly from her after 12 seconds?

Solution:

### NCERT Solutions for Class 10 Maths

- Chapter 1 Real Numbers
- Chapter 2 Polynomials
- Chapter 3 Pair of Linear Equations in Two Variables
- Chapter 4 Quadratic Equations
- Chapter 5 Arithmetic Progressions
- Chapter 6 Triangles
- Chapter 7 Coordinate Geometry
- Chapter 8 Introduction to Trigonometry
- Chapter 9 Some Applications of Trigonometry
- Chapter 10 Circles
- Chapter 11 Constructions
- Chapter 12 Areas Related to Circles
- Chapter 13 Surface Areas and Volumes
- Chapter 14 Statistics
- Chapter 15 Probability

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