Get Free **NCERT Solutions for Class 10 Maths Chapter 13** Ex 13.1 PDF. Surface Areas and Volumes Class 10 Maths NCERT Solutions are extremely helpful while doing your homework. Exercise 13.1 Class 10 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 13 Maths **Class 10 Surface Areas and Volumes** Exercise 13.1 provided in NCERT TextBook.

- Surface Areas and Volumes Class 10 Ex 13.1
- Surface Areas and Volumes Class 10 Ex 13.2
- Surface Areas and Volumes Class 10 Ex 13.3
- Surface Areas and Volumes Class 10 Ex 13.4
- Surface Areas and Volumes Class 10 Ex 13.5
- Extra Questions for Class 10 Maths Surface Areas and Volumes

Section Name | Topic Name |

13 | Surface Areas And Volumes |

13.1 | Introduction |

13.2 | Surface Area Of A Combination Of Solids |

13.3 | Volume Of A Combination Of Solids |

13.4 | Conversion Of Solid From One Shape To Another |

13.5 | Frustum Of A Cone |

13.6 | Summary |

## NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.1

NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.1 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.1.

Board | CBSE |

Textbook | NCERT |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 13 |

Chapter Name | Surface Areas and Volumes |

Exercise | Ex 13.1 |

Number of Questions Solved | 9 |

Category | NCERT Solutions |

Question 1.

2 cubes each of volume 64 cm^{3} are joined end to end. Find the surface area of the resulting cuboid.

Solution:

Question 2.

A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm. Find the inner surface area of the vessel.

Solution:

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Download NCERT Solutions For Class 10 Maths Chapter 13 Surface Areas and Volumes PDF

Question 3.

A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of the same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy.

Solution:

Question 4.

A cubical block of side 7 cm is surmounted by a hemisphere. What is the greatest diameter the hemisphere can have? Find the surface area of the solid.

Solution:

Question 5.** **A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter d of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid.

Solution:

Question 6.** **A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends. The length of the entire capsule is 14 mm and the diameter of the capsule is 5 mm. Find its surface area.

Solution:

Question 7.

A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 500 per m^{2}. (Note that the base of the tent will not be covered with canvas.)

Solution:

Question 8.

From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm^{2}.

Solution:

Question 9.

A wooden article was made by scooping out a hemisphere from each end of a solid cylinder, as shown in figure. If the height of the cylinder is 10 cm, and its base is of radius 3.5 cm, find the total surface area of the article.

Solution:

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