## RD Sharma Class 10 Solutions Chapter 9 Arithmetic Progressions Ex 9.2

### RD Sharma Class 10 Solutions Arithmetic Progressions Exercise 9.2

Question 1.

Show that the sequence defined by a_{n} = 5n – 7 is an A.P., find its common difference.

Solution:

Question 2.

Show that the sequence defined by a_{n} = 3n² – 5 is not an A.P.

Solution:

Question 3.

The general term of a sequence is given by a_{n} = -4n + 15. Is the sequence an A.P.? If so, find its 15th term and the common difference.

Solution:

General term of a sequence

a_{n} = -4n + 15

Question 4.

Write the sequence with nth term :

(i) a_{n} = 3 + 4n

(ii) a_{n} = 5 + 2n

(iii) a_{n} = 6 – n

(iv) a_{n} = 9 – 5n

Show that all of the above sequences form A.P.

Solution:

Question 5.

The nth term of an A.P. is 6n + 2. Find the common difference. [CBSE 2008]

Solution:

Question 6.

Justify whether it is true to say that the sequence, having following nth term is an A.P.

(i) a_{n} = 2n – 1

(ii) a_{n} = 3n² + 5

(iii) a_{n} = 1 + n + n²

Solution: