Get Free **NCERT Solutions for Class 10 Maths Chapter 1 PDF**. Real Numbers Class 10 Maths NCERT Solutions are extremely helpful while doing homework. **Ex 1.1 Chapter 1 Class 10 Maths NCERT Solutions** were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 1 maths class 10 Real Numbers Exercise 1.1 provided in NCERT Textbook.

- Real Numbers Class 10 Ex 1.1
- Real Numbers Class 10 Ex 1.2
- Real Numbers Class 10 Ex 1.3
- Real Numbers Class 10 Ex 1.4
- NCERT Solutions for Class 10 Maths

Section Name | Topic Name |

1.1 | Introduction |

1.2 | Euclid’s Division Lemma |

1.3 | The Fundamental Theorem Of Arithmetic |

1.4 | Revisiting Irrational Numbers |

1.5 | Revisiting Rational Numbers And Their Decimal Expansions |

1.6 | Summary |

## NCERT Solutions For Class 10 Maths Chapter 1 Real Numbers Ex 1.1

NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 1.1 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 1.1

Board | CBSE |

Textbook | NCERT |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 1 |

Chapter Name | Real Numbers |

Exercise | Ex 1.1 |

Number of Questions Solved | 5 |

Category | NCERT Solutions |

Question 1.

Use Euclid’s Division Algorithm to find the HCF of:

(i) 135 and 225

(ii) 196 and 38220

(iii) 867 and 255

Solution:

Question 2.

Show that any positive odd integer is of the form 6q + 1, or 6q + 3, or 6q + 5, where q is some integer.

Solution

Question 3.

An army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?

Solution:

Question 4.

Use Euclid’s division lemma to show that the square of any positive integer is either of the form 3m or 3m + 1 for some integer m.

Solution:

Question 5.

Use Euclid’s Division Lemma to show that the cube of any positive integer is either of the form 9m, 9m + 1 or 9m + 8.

Solution:

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Real Numbers Class 10 Maths NCERT Solutions PDF Download

### Class 10 Maths Real Numbers

Rational numbers and irrational numbers are taken together form the set of real numbers. The set of real numbers is denoted by R. Thus every real number is either a rational number or an irrational number. In either case, it has a non–terminating decimal representation. In the case of rational numbers, the decimal representation is repeating (including repeating zeroes) and if the decimal representation is non–repeating, it is an irrational number. For every real number, there corresponds a unique point on the number line ‘l’ or we may say that every point on the line ‘l’ corresponds to a real number (rational or irrational).

From the above discussion we may conclude that:

To every real number there corresponds a unique point on the number line and conversely, to every point on the number line there corresponds a real number. Thus we see that there is one–to–one correspondence between the real numbers and points on the number line ‘l’, that is why the number line is called the ‘real number line’.

### Real Numbers Class 10 Maths Objectives

The students will be able to ;

prove Euclid’s Division Lemma

state fundamental theorem of arithmetic

find HCF and LCM using prime factorization

establish the given number as an irrational number

conclude the decimal expansion of a rational number is either terminating or non-terminating repeating.

### Chapter 1 Class 10 Maths Real Numbers Summary

We have studied the following points:

1. Euclid’s Division Lemma: Given positive integers a and b, there exist whole numbers q and r satisfying a = bq + r where 0 = r = b.

2. Euclid’s Division Algorithm: According to this, which is based on Euclid’s division lemma, the HCF of any two positive integers a and b with a > b is obtained as follows:

Step 1 Apply the division lemma to find q and r where a = bq + r, O = r < b.

Step 2 If r = 0, the HCF is b . If r? 0 apply Euclid Lemma to b and r

Step 3 Continue the process until the remainder is zero. The divisor at this stage will be HCF (a, b). Also HCF (a, b) = HCF (b, r)

3. The Fundamental Theorem of Arithmetic: Every composite number can be expressed (factorized) as a product of primes and this factorization is unique, apart from the order in which the prime factors occur.

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