Get Free NCERT Solutions for Class 10 Maths Chapter 8 Ex 8.3 Introduction to Trigonometry Class 10 Maths NCERT Solutions are extremely helpful while doing homework. Exercise 8.3 Class 10 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 8 Maths Class 10 Coordinate Geometry Exercise 8.3 Provided in NCERT Textbook.

**Topics and Sub Topics in Class 10 Maths Chapter 8 Introduction to Trigonometry:**

Section Name | Topic Name |

8 | Introduction to Trigonometry |

8.1 | Introduction |

8.2 | Trigonometric Ratios |

8.3 | Trigonometric Ratios Of Some Specific Angles |

8.4 | Trigonometric Ratios Of Complementary Angles |

8.5 | Trigonometric Identities |

8.6 | Summary |

- Introduction to Trigonometry Class 10 Ex 8.1
- Introduction to Trigonometry Class 10 Ex 8.2
- Introduction to Trigonometry Class 10 Ex 8.3
- Introduction to Trigonometry Class 10 Ex 8.4
- Extra Questions for Class 10 Maths Introduction to Trigonometry

You can also download the free PDF of Chapter 8 Ex 8.3 Coordinate Geometry NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation.

Board | CBSE |

Textbook | NCERT |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 8 |

Chapter Name | Introduction to Trigonometry |

Exercise | Ex 8.3 |

Number of Questions Solved | 7 |

Category | NCERT Solutions |

## NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3

NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3.

Question 1.

Evaluate:

Solution:

Question 2.

Show that:

(i) tan 48° tan 23° tan 42° tan 67° = 1

(ii) cos 38° cos 52° – sin 38° sin 52° = 0

Solution:

Download NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry PDF

Question 3.

If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A.

Solution:

Question 4.

If tan A = cot B, prove that A + B = 90°.

Solution:

Question 5.

If sec 4A = cosec (A – 20°), where 4A is an acute angle, find the value of A.

Solution:

Question 6.

If A, B and C are interior angles of a triangle ABC, then show that: sin () = cos

Solution:

Question 7.

Express sin 61° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.

Solution:

### NCERT Solutions for Class 10 Maths

- Chapter 1 Real Numbers
- Chapter 2 Polynomials
- Chapter 3 Pair of Linear Equations in Two Variables
- Chapter 4 Quadratic Equations
- Chapter 5 Arithmetic Progressions
- Chapter 6 Triangles
- Chapter 7 Coordinate Geometry
- Chapter 8 Introduction to Trigonometry
- Chapter 9 Some Applications of Trigonometry
- Chapter 10 Circles
- Chapter 11 Constructions
- Chapter 12 Areas Related to Circles
- Chapter 13 Surface Areas and Volumes
- Chapter 14 Statistics
- Chapter 15 Probability

We hope the NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3, help you. If you have any query regarding NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.3, drop a comment below and we will get back to you at the earliest.

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