## NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5

- Class 7 Maths Practical Geometry Exercise 10.1
- Class 7 Maths Practical Geometry Exercise 10.2
- Class 7 Maths Practical Geometry Exercise 10.3
- Class 7 Maths Practical Geometry Exercise 10.4
- Class 7 Maths Practical Geometry Exercise 10.5

**NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.5**

Ex 10.5 Class 7 Maths Question 1.

Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.

Solution:

Steps of construction:

(i) Draw QR = 8 cm.

(ii) Draw m∠Q = 90°.

(iii) Draw an arc with centre R and radius 10 cm to cut the perpendicular line at P.

(iv) ∆PQR is the required triangle.

[Using RHS criterion]

Ex 10.5 Class 7 Maths Question 2.

Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

Solution:

Steps of construction:

(i) Draw AB = 4 cm.

(ii) Draw ∠A = 90°.

(iii) Cut BC = 6 cm.

(iv) ∆CAB is the required right-angled triangle.

[Using RHS criterion]

Ex 10.5 Class 7 Maths Question 3.

Construct an isosceles right-angled triangle ABC, where m∠ACB = 90° and AC = 6 cm.

Solution:

Steps of construction:

(i) Draw AC = 6 cm.

(ii) Draw ∠A =∠C = 45° to meet each other at B such that m∠B = 90°.

(iii) ∆ABC is right-angled isosceles triangle which is the required triangle.

[Using RHS criterion]

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Mayank says

Nice answer

Trisan ghosh says

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