## NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3

- Class 7 Maths Practical Geometry Exercise 10.1
- Class 7 Maths Practical Geometry Exercise 10.2
- Class 7 Maths Practical Geometry Exercise 10.3
- Class 7 Maths Practical Geometry Exercise 10.4
- Class 7 Maths Practical Geometry Exercise 10.5

**NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.3**

Ex 10.3 Class 7 Maths Question 1.

Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m ∠DEF = 90°.

Solution:

Steps of construction:

(i) Draw DF = 3 cm.

(ii) Draw an angle of 90° at D and cut DE = 5 cm.

(iii) Join EF.

(iv) EPF is the required triangle.

Using SAS property

Ex 10.3 Class 7 Maths Question 2.

Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110°.

Solution:

Steps of construction:

(i) Draw AB = 6.5 cm.

(ii) Draw angle of 110° at A and cut AC = 6.5 cm.

(iii) Join C to B.

(iv) CAB is the required triangle.

[Using SAS criterion]

Ex 10.3 Class 7 Maths Question 3.

Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m ∠C = 60°.

Solution:

Steps of construction:

(i) Draw BC = 7.5 cm.

(ii) Draw ∠C = 60° such that AC = 5 cm.

(iii) Join A to B.

(iv) ABC is the required triangle.

[Using SAS Criterion]

NCERT SolutionsMathsScienceSocialEnglishSanskritHindiRD Sharma