## NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2

- Class 7 Maths Perimeter and Area Exercise 11.1
- Class 7 Maths Perimeter and Area Exercise 11.2
- Class 7 Maths Perimeter and Area Exercise 11.3
- Class 7 Maths Perimeter and Area Exercise 11.4

**NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Exercise 11.2**

Ex 11.2 Class 7 Maths Question 1.

Find the area of each of the following parallelograms:

Solution:

(a) Area of the parallelogram

= base × altitude = 7 cm × 4 cm

= 28 cm^{2}

(b) Area of the parallelogram

= base × altitude = 5 cm × 3 cm

= 15 cm^{2}

(c) Area of the parallelogram

= base × altitude = 2.5 cm × 3.5 cm

= 8.75 cm^{2}

(d) Area of the parallelogram

= base × altitude = 5 cm × 4.8 cm

= 24.0 cm^{2}

(e) Area of the parallelogram

= base × altitude = 2 cm × 4.4 cm

= 8.8 cm^{2}

Ex 11.2 Class 7 Maths Question 2.

Find the area of each of the following triangles:

Solution:

Area of the triangle = × b × h

= × 4 cm × 3 cm

= 6m^{2}

(b) Area of the triangle = × b × h

= × 5 cm × 3.2 cm

= 8.0 cm^{2}

(c) Area of the triangle = × b × l

= × 3 cm × 4 cm

= 6 cm^{2}

(d) Area of the triangle = × b × h

= × 3 cm × 2 cm

= 3 cm^{2}

Ex 11.2 Class 7 Maths Question 3.

Find the missing values:

S.No. | Base | Height | Area of the parallelogram |

(a) | 20 cm | 246 cm^{2} | |

(6) | 15 cm | 154.5 cm^{2} | |

(c) | 8.4 cm | 48.72 cm^{2} | |

(d) | 15.6 | 16.38 cm^{2} |

Solution:

(a) Area of the parallelogram =b × h

246 = 20 × h

(b) Area of the parallelogram = b × h

154.5 = b × 15

(c) Area of the parallelogram = b × h

48.72 = b × 8.4

(d) Area of the parallelogram = b × h

16.38 = 15.6 × h

Ex 11.2 Class 7 Maths Question 4.

Find the missing values:

Base | Height | Area of the triangle |

15 cm | — | 87 cm^{2} |

— | 31.4 mm | 1256 mm^{2} |

22 cm | — | 170.5 cm^{2} |

Solution:

(i) Area of the triangle = × b × h

So, the height =11.6 cm

(ii) Area of the triangle = × b × h

So, the required base = 80 mm.

(iii) Area of the triangle = × b × h

So, the required height = 15.5 cm

Ex 11.2 Class 7 Maths Question 5.

PQRS is a parallelogram. QM is the height of Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:

(a) the area of the parallelogram PQRS

(b) QN, if PS = 8 cm

Solution:

(a) Area of the parallelogram PQRS

= SR × QM (∵ Area = Base × Height)

= 12 cm × 7.6 cm

= 91.2 cm^{2}

(b) Area of the parallelogram PQRS

Ex 11.2 Class 7 Maths Question 6.

DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD. If the area of the parallelogram is 1470 cm^{2}, AB = 35 cm and AD = 49 cm, find the length of BM and DL.

Solution:

Area of the parallelogram ABCD

= AB × DL

⇒ 1470 cm^{2} = 35 cm × DL

⇒ DL

∴ DL = 42 cm

Area of the parallelogram ABCD = AD × BM

1470 cm^{2} = 49 cm × BM

⇒ = 30 cm

∴ BM = 30 cm

Hence, BM = 30 cm and DL = 42 cm

Ex 11.2 Class 7 Maths Question 7.

∆ABC is right angled at A. AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of ∆ABC. Also find the length of AD.

Solution:

Area of right triangle ABC

Ex 11.2 Class 7 Maths Question 8.

∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height AD from A to BC, is 6 cm. Find the area of ∆ABC. What will be the height from C to AB i.e., CE?

Solution:

Area of ∆ABC = × base × height

NCERT SolutionsMathsScienceSocialEnglishSanskritHindiRD Sharma

mrinalini says

best one ever

maithali says

Superb

Swaraj Gupta says

They are good helping for my math practice .. it was good

Debjyoti says

Excellent

Akash singh says

Superb mera home work ho jata hai

Kanaka says

Yes

Kanaka says

Superb

Tanisha jadon says

Useful

Tanisha jadon says

Veryuseful

Himanshu yadav says

Fantastic answers of ncert whole syllabus

Himanshu yadav says

Fantastic answers of whole syllabus

likith says

supeeeeeer!!!!!!!!!!!!!!!!!!!!!!!!!!1

Rishi says

Your app

Ujjwal says

It’s very helpful

Roshini says

Its helps me to know more

Harmeet says

Fabulous app for maths

ARIf says

Helping

Jiya says

Helps in math peactise……….nice

Srishti says

It’s good.. . It’s really very good.. .

Maahi Mirza says

Superb.I do my maths sums with this website very easily.

archana says

this is very good app for us

archana says

yes

Shri ananya says

Superb. It helps me to do very quick and makes me understand very easy. Thank u for the team.

Saudamini Malladi says

Awesome

khushi bhati says

Super

Vansh says

I like it very much. It helps me in my exams. Wah Wah Wah Wah very good

Vansh says

It is very useful. I helps me so much

Sreekar says

Its actually good but dot give such big answers please……

My rating is 4 stars out of 5

Ayisha says

This aap is best

Anjana says

This are good for students

Anjana says

This are good for students and I love this vebsite

Mukul says

This website is very very good it helps me a lot.Very good keep it up..

Anita kumari says

We get support from your website thank u very much for your help