## NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.4

- Class 7 Maths Integers Exercise 1.1
- Class 7 Maths Integers Exercise 1.2
- Class 7 Maths Integers Exercise 1.3
- Class 7 Maths Integers Exercise 1.4

**NCERT Solutions for Class 7 Maths Chapter 1 Integers Exercise 1.4**

Ex 1.4 Class 7 Maths Question 1.

Evaluate each of the following:

(a) (-30) ÷ 10

(b) 50 ÷ (-5)

(c) (-36) ÷ (-9)

(d) (-49) ÷ (49)

(e) 13 ÷ [(-2) + 1]

(f) 0 ÷ (-12)

(g) (-31) ÷ [(-30) + (-1)]

(h) [(-36) ÷ 12] ÷ 3

(i) [(-6) + 5] ÷ [(-2) + 1]

Solution:

(a) (-30) ÷ 10 = \(\frac{-30}{10}\) = -3 50

(b) 50 ÷ (-5) = \(\frac{50}{-5}\) = -10

(c) (-36) ÷ (-9) = \(\frac{-36}{-9}\) = 4

(d) (-49) ÷ (49) = \(\frac{-49}{49}\) = -1

(e) 13 ÷ [(-2) + 1] = 13 ÷ -1 = \(\frac{13}{-1}\) = -13

(f) 0 ÷ (-12) = \(\frac{0}{-12}\) = 0

(g) (-31) ÷ [(-30) + (-1)] = (-31) ÷ (-31) = \(\frac{-31}{-31}\) = 1

(h) [(-36) + 12] ÷ 3 = \(\left[-\frac{36}{12}\right]\) ÷ 3 = -3 ÷ 3

= \(\frac{-3}{3}\) =-1

(i) [(-6) + 5] + [(-2) + 1] = (-1) – (-1) = \(\frac{-1}{-1}\) = 1

Ex 1.4 Class 7 Maths Question 2.

Verify that: a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c) for each of the following values of a, b and c.

(а) a = 12, b = – 4, c = 2

(b) a = (-10), b = 1, c = 1

Solution:

(a) a = 12, 6 = – 4, c = 2

a ÷ (b + c) = 12 ÷ [(-4) + 2]

= 12 ÷ (-2) = \(\frac{12}{-2}\) = -6

(a ÷ b) + (a ÷ c) = [12 ÷ (-4)] + [12 ÷ 2]

\(=\frac{12}{-4}+\frac{12}{2}=-3+6=3\)

Since, (-6) + 3

Hence, a ÷ (b + c) + (a ÷ b) + (a ÷ c)

(b) a = (-10), b = 1, c = 1

a ÷ (b + c) = (-10) ÷ (1 + 1)

=(-10) ÷ 2 = \(\frac{-10}{2}\) = -5

(a ÷ b) + (a ÷ c)

=[(-10) ÷ 1] + [(-10) ÷ 1]

\(=\frac{(-10)}{1}+\frac{(-10)}{1}\)

= (-10) + (-10) = -20

Since (-5) ≠ (-20)

Hence, a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)

Ex 1.4 Class 7 Maths Question 3.

Fill in the blanks:

(a) 369 ÷ ___ = 369

(b) (-75) ÷ ___ = -1

(c) (-206) ÷ ___ =1

(d) -87 ÷ ___ = -87

(e) ___ ÷ 1 = -87

(g) 20 ÷ ___ = -2

Solution:

(a) 369 ÷ ___ = 369 = 369 ÷ 1 = 369

(b) (-75) ÷ ___ = -1 = (-75) ÷ 75 = -1

(c) (-206) ÷ ___ = 1 = (-206) ÷ (-206) = 1

(d) 87 ÷ ___ = 87 = -87 ÷ (-1) = 87

(e) ___ ÷ 1 = -87 = -87 ÷ 1 = -87

(f) ___ ÷ 48 = -1 = (-48) ÷ 48 = -1

(g) 20 + ___ = -2 = 20 ÷ (-10) = -2

(h) ___ + (4) = -3 = (-12) ÷ (4) = -3

Ex 1.4 Class 7 Maths Question 4.

Write five pairs of integers (a, b) such that a ÷ b = -3. One such pair is (6, -2) because 6 + (-2) = -3.

Solution:

(a) (24, -8) because 24 ÷ (-8) = -3

(b) (-12, 4) because (-12) ÷ 4 = -3

(c) (15, -5) because 15 ÷ (-5) = -3

(d) (18, -6) because 18 ÷ (-6) = -3

(e) (60, -20) because 60 ÷ (-20) = -3

Ex 1.4 Class 7 Maths Question 5.

The temperature at 12 noon was 10°C above zero. If it decreases at the rate of 2°C per hour until midnight, at what time would the temperature be 8°C below zero? What would be the temperature at midnight?

Solution:

Temperature at 12 noon was 10°C above zero i.e. +10°C

Rate of decrease in temperature per hour = 2°C

Number of hours from 12 noon to midnight = 12

∴ Change in temperature in 12 hours

= 12 × (-2°C) = -24°C

∴ Temperature at midnight

= +10°C + (-24°C) = -14°C

Hence, the required temperature at midnight =-14°C

Difference in temperature between + 10°C and -8°C

= +10°C – (-8°C) = +10°C + 8°C = 18°C

Number of hours required = \(\frac{18^{\circ} \mathrm{C}}{2^{\circ} \mathrm{C}}\)= 9 hours

∴ Time after 9 hours from 12 noon = 9 pm.

Ex 1.4 Class 7 Maths Question 6.

In a class test (+3) marks are given for every correct answer and (-2) marks are given for every incorrect answer and no marks for not attempting any question:

(i) Radhika scored 20 marks. If she has got 12 correct answers, how many questions has she attempted incorrectly?

(ii) Mohini scores -5 marks in this test, though she has got 7 correct answers. How many questions has she attempted incorrectly?

Solution:

Given that:

+3 marks are given for each correct answer. (-2) marks are given for each incorrect answer. Zero marks for not attempted questions.

(i) Marks obtained by Radhika for 12 correct answers = (+3) × 12 = 36

Marks obtained by Radhika for correct answers = 12 × 3 = 36

Total marks obtained by Radhika = 20

∴ Marks obtained by Radhika for incorrect answers = 20 – 36 = -16

Number of incorrect answers

\(=(-16) \div(-2)=\frac{(-16)}{(-2)}=8\)

Hence, the required number of incorrect answers = 8

(ii) Marks scored by Mohini = -5

Number of correct answers = 7

∴ Marks obtained by Mohini for 7 correct answers = 7 × (+3) – 21

Marks obtained for incorrect answers

= -5 – 21 = (-26)

∴ Number of incorrect answers

= (-26) ÷ (-2) = 13

Hence, the required number of incorrect answers – 13.

Ex 1.4 Class 7 Maths Question 7.

An elevator descends into a nine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach -350 m.

Solution:

The present position of the elevator is at 10 in above the ground level.

Distance moved by the elevator below the ground level = 350 m

∴ Total distance moved by the elevator = 350 m + 10 m = 360 m

Rate of descent = 6 m/min.

Total time taken by the elevator

\(=\frac{360 \mathrm{m}}{6 \mathrm{m} / \mathrm{min}}\)

= 60 minutes = 1 hour

Hence, the required time = 1 hour.

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