## NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

- Class 7 Maths Fractions and Decimals Exercise 2.1
- Class 7 Maths Fractions and Decimals Exercise 2.2
- Class 7 Maths Fractions and Decimals Exercise 2.3
- Class 7 Maths Fractions and Decimals Exercise 2.4
- Class 7 Maths Fractions and Decimals Exercise 2.5
- Class 7 Maths Fractions and Decimals Exercise 2.6
- Class 7 Maths Fractions and Decimals Exercise 2.7

**NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.5**

Ex 2.5 Class 7 Maths Question 1.

Which is greater?

(i) 0.5 or 0.05

(ii) 0.7 or 0.5

(iii) 7 or 0.7

(iv) 1.37 or 1.49

(v) 2.03 or 2.30

(vi) 0.8 or 0.88

Solution:

(i) 0.5 or 0.05

Comparing the tenths place, we get 5 > 0

∴ 0.5 > 0.05

(ii) 0.7 or 0.5

Comparing the tenths place, we get 7 > 5

∴ 0.7 > 0.5

(iii) 7 or 0.7

Comparing the one’s place, we get 7 > 0

∴ 7 > 0.7

(iv) 1.37 or 1.49

Comparing the tenths place, we get 3 < 4

∴ 1.37 < 1.49 or 1.49 > 1.37

(v) 2.03 or 2.30

Comparing the tenths place, we get 0 < 3

∴ 2.03 < 2.30 or 2.30 > 2.03

(vi) 0.8 or 0.88 ⇒ 0.80 or 0.88

Since tenths place is same.

Comparing the hundredth place, we get 0 < 8

∴ 0.80 < 0.88 or 0.88 > 0.80

Ex 2.5 Class 7 Maths Question 2.

Express as rupees using decimals:

(i) 7 paise

(ii) 7 rupees 7 paise

(iii) 77 rupees 77 paise

(iv) 50 paise

(v) 235 paise

Solution:

(i) Since 1 rupee = 100 paise and 1 paise = \(\frac{1}{100}\) rupees

7 paise =\(\frac{7}{100}\) rupees = 0.07 rupees

(ii) 7 rupees 7 paise = 7 rupees + \(\frac{7}{100}\) rupees

= 7.07 rupees

(iii) 77 rupees 77 paise = 77 rupees + \(\frac{77}{100}\) rupees

= 77.77 rupees

(iv) 50 paise = \(\frac{50}{100}\) rupees = 0.50 rupees

(v) 235 paise = \(\frac{235}{100}\) rupees = 2.35 rupees

Ex 2.5 Class 7 Maths Question 3.

(i) Express 5 cm in metre and kilometre

(ii) Express 35 mm in cm, m and km.

Solution:

(i) 1 metre = 100 cm

1 kilometre = 1000 metre = 100 × 1000 cm

= 100000 cm

∴ 5 cm = \(\frac{5}{100}\) metre = 0.05 metre

5 cm = \(\frac{5}{100000}\) km = 0.00005 km

Hence, 5 cm = 0.05 m and 0.00005 km

(ii) 1 cm = 10 mm and 1 km = 100000 cm

∴ 35 mm = \(\frac{35}{10}\) cm = 3.5 cm,

35 mm = \(\frac{35}{1000}\) m = 0.035 m

35 mm = \(\frac{35}{1000000}\) km = 0.000035 km

Hence, 35 mm = 3.5 cm, 0.035 m and 0.000035 km.

Ex 2.5 Class 7 Maths Question 4.

Express in kg:

(i) 200 g

(ii) 3470 g

(iii) 4 kg 8 g

Solution:

(i) 200g = \(\frac{200}{1000}\) kg [∵ 1 kg = 1000g]

= 0.2 kg

(ii) 3470 g = \(\frac{3470}{10000}\) = 3.47 kg [∵ 1 kg = 1000 g]

(iii) 4 kg 8 g = 4 kg + \(\frac{8}{10000}\)kg [∵ 1 kg = 1000 g]

= 4 kg + 0.008 kg = 4.008 kg

Ex 2.5 Class 7 Maths Question 5.

Write the following decimal numbers in the expanded form:

(i) 20.03

(ii) 2.03

(iii) 200.03

(iv) 2.034

Solution:

(i) 20.03 = 2 × 10 + 0 × 1 + 0 × \(\frac{1}{10}\) + 3 × \(\frac{1}{100}\)

(ii) 2.03 = 2 × 1 + 0 × \(\frac{1}{10}\) + 3 × \(\frac{1}{100}\)

(iii) 200.03 = 2 × 100 + 0 × 10 + 0 × 1 + 0 × \(\frac{1}{10}\) +3 × \(\frac{1}{100}\)

(iv) 2.034 = 2 × 1 + 0 × \(\frac{1}{10}\) + 3 × \(\frac{1}{10}\) + 4 × \(\frac{1}{1000}\)

Ex 2.5 Class 7 Maths Question 6.

Write the place value of 2 in the following decimal numbers:

(i) 2.56

(ii) 21.37

(iii) 10.25

(iv) 9.42

(v) 63.352

Solution:

(i) Place value of 2 in 2.56 = 2 × 1 = 2 i.e. ones

(ii) Place value of 2 in 21.37 = 2 × 10 = 20 i.e. tens

(iii) Place value of 2 in 10.25 = \(\frac{2}{10}\) = 0.2 i.e. tenths

(iv) Place value of 2 in 9.42 = \(\frac{2}{100}\) = 0.02 i.e. hundredths

(v) Place value of 2 in 63.352 = \(\frac{2}{1000}\) = 0.002 i.e. thousandths.

Ex 2.5 Class 7 Maths Question 7.

Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?

Solution:

Distance travelled by Dinesh from A to C

= AB + BC

= 7.5 km +- 12.7 km

= 20.2 km

Distance travelled by Ayub from A to C

= AD + DC

= 9.3 km + 11.8 km = 21.1 km

Since 21.1 km > 20.2 km.

Hence, Ayub travelled more distance.

Ex 2.5 Class 7 Maths Question 8.

Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?

Solution:

Fruits bought by Shyama

= 5 kg 300 g apples + 3 kg 250 g mangoes

= 5.300 kg apples + 3.250 kg mangoes

= 8.550 kg of fruits

Fruits bought by Sarala

= 4 kg 800 g oranges +- 4 kg 150 g bananas

= 4.800 kg oranges + 4.150 kg bananas

= 8.950 kg of fruits

Since 8.950 kg > 8.550 kg

Hence, Sarala bought more fruits.

Ex 2.5 Class 7 Maths Question 9.

How much less is 28 km than 42.6 km?

Solution:

Since 28 km < 42.6 km

Hence, 28 km is less than 42.6 km by 14.6 km.

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