## NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles Ex 7.2

- Class 7 Maths Congruence of Triangles Exercise 7.1
- Class 7 Maths Congruence of Triangles Exercise 7.2

**NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles Exercise 7.2**

Ex 7.2 Class 7 Maths Question 1.

Which congruence criterion do you use in the following?

(a) Given:

AC = DF

AB = DE

BC = EF

So, ∆ABC = ∆DEF

(b) Given:

ZX = RP

RQ = ZY

∠PRQ = ∠XZY

So, ∆PQR ≅ ∆XYZ

(c) Given: ∠MLN = ∠FGH

∠NML = ∠GFH

ML = FG

So, ∆LMN = ∆GFH

(d) Given:

EB = DB

AE = BC

∠A = ∠C = 90°

∆ABE = ∆CDB

Solution:

(a) ∆ABC ≅ ∆DEF (BY SSS rule)

(b) ∆PQR ≅ ∆XYZ (BY SAS rule)

(c) ∆LMN ≅ ∆GFH (BY ASA rule)

(d) ∆ABE ≅ ∆CDB (BY RHS rule)

Ex 7.2 Class 7 Maths Question 2.

You want to show that ∆ART = ∆PEN,

(a) If you have to use SSS criterion, then you need to show

(i) AR =

(ii) RT =

(iii) AT =

(b) If it is given that ∠T = ∠N and you are to use SAS criterion, you need to have

(i) RT = and

(ii) PN =

(c) If it is given that AT = PN and you are to use ASA criterion, you need to have

(i) ZA

(ii) ZT

Solution:

(a) For SSS criterion, we need

(i) AR = PE

(ii) RT = EN

(iii) AT = PN

(b) For SAS criterion, we need

(i) RT = EN and

(ii) PN = AT

(c) For ASA criterion, we need

(i) ∠A = ∠P

(ii) ∠T = ∠N

Ex 7.2 Class 7 Maths Question 3.

You have to show that ∆AMP ≅ ∆AMQ. In the fallowing proof, supply the missing reasons.

Steps | Reasons | |

(i) PM = QM | (i) | |

(ii) ∠PMA – ∠QMA | (ii) | |

(iii) AM = AM | (iii) | |

(iv) ∆AMP = ∆AMQ | (iv) |

Solution:

Steps | Reasons | |

(i) PM = QM | (i) Given | |

(ii) ∠PMA = ∠QMA | (ii) Given | |

(iii) AM = AM | (iii) Common | |

(iv) ∆AMP = ∆AMQ | (iv) SAS rule |

Ex 7.2 Class 7 Maths Question 4.

In ∆ABC, ∠A = 30°, ∠B = 40° and ∠C = 110°

In ∆PQR, ∠P = 30°, ∠Q = 40° and ∠R = 110°.

A student says that ∆ABC = ∆PQR by AAA congruence criterion. Is he justified? Why or why not?

Solution:

The student is not justified because there is not criterion for AAA congruence rule.

Example: In ∆ABC and ∆PQR, we have ∠A = 30°, ∠B = 40°, ∠C = 110°

∠P = 30°, ∠Q = 40°, ∠R = 110°

But ∆ABC is not congruent to ∆PQR.

Ex 7.2 Class 7 Maths Question 5.

In the figure, the two triangles are congruent. The corresponding parts are marked. We can write ∆RAT ≅ ?

Solution:

In ∆RAT and ∆WON

(Given)

(Given)

∠A = ∠O (Given)

∴ ∆RAT ≅ ∆WON (By SAS rule)

Ex 7.2 Class 7 Maths Question 6.

Complete the congruence statement:

Solution:

Refer to Fig. (i)

In ∆BCA and ∆BTA

∠C = ∠T (Given)

(Given)

∠BA = ∠TBA (Given)

∴ ∆BCA = ∆BTA (by ADA rule)

Refer to Fig. (ii)

In ∆QRS and ∆TPQ

(Given)

(Given)

∠RSQ = ∠PQT (Given)

∴ ∆QRS = ∆TPQ (by SAS rule)

Ex 7.2 Class 7 Maths Question 7.

In a squared sheet, draw two triangles of equal areas such that:

(i) the triangles are congruent.

(ii) the triangle are not congruent.

What can you say about their perimeters?

Solution:

(i) On the given square sheet, we have draw two congruent triangles i.e.

∆ABC = ∆DEF

such that

On adding, we get

i.e. perimeters of ∆ABC = Perimeter of ∆DEF

(ii) On the other square sheet, we have drawn two triangles ABC and PQR which are not congruent.

Such that

Adding both sides, we get

i.e., perimeter of ∆ABC ≠ the perimeter of ∆PQR.

Ex 7.2 Class 7 Maths Question 8.

Draw a rough sketch of two triangles, such that they have five pairs of congruent parts but still

the triangles are not congruent.

Solution:

We have ∆PQR and ∆TSU

(Given)

(Given)

∠Q = ∠S (Given)

∠P = ∠T (Given)

∠R = ∠U (Given)

Since non of the criteria of congruence is relevant here.

∴ ∆PQR and ∆TSU are not congruent.

Ex 7.2 Class 7 Maths Question 9.

If ∆ABC and ∆PQR are to be congruent, name one additional pair of corresponding parts. What criterion did you use?

Solution:

In ∆ABC and ∆PQR

∠B = ∠Q (Given)

∠C = ∠R (Given)

For ∆ABC = ∆PQR

BC must equal to criterion that we used is ASA rule.

Hence, the additional pair of corresponding part is .

Ex 7.2 Class 7 Maths Question 10.

Explain, why ∆ABC = ∆FED

Solution:

In ∆ABC and ∆FED

∠B = ∠E = 90° (Given)

∠A = ∠F (Given)

∴ ∠A + ∠B = ∠E + ∠F

180° – ∠C = 180° – ∠D

[Angle sum property of triangles]

∴ ∠C =∠D

BC = ED (Given)

∴ ∆ABC = ∆FED (By ASA rule)

**Question 8.**

Draw a rough sketch of two triangles such that they have five pairs of congruent parts but still the triangles are not congruent.

**Solution:**

In some special cases (which depend on the lengths of the sides and the size of the angle involved),

SSA is enough to show congruence. However, it is not always enough. Consider the following triangles :

Here side AB is congruent to side DE (S) side AC is congruent to side DF(S) angle C is congruent to angle F(A)

But the triangles are not congruent, as we can see.

**What happens is this :** If we draw a vertical line through point A in the first triangle, we can sort of “flip” side AB around this line to get the second triangle. If we were to lay one triangle on top of the other and draw the vertical line, this how it would look.

Clearly, side DE is just side AB flipped around the line. So, we have not changed the length of the side, and the other side AC (or DF) is unchanged, as is angle C (or F). So, these two triangles that have the same SSA information, but they are not congruent.

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PRADEEP Kumar says

Thanks it was great but in last question u should write that triangle are congurent by AAA

Ishant says

AAA is not any property

1. Sss

2. ASA

3. SAS

4. Rhs

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Aditi says

AAA congruence criterion is not there because one side should me mentioned atleast

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But where is question 8 the most confusing question

Priyanshi Mishra says

There is no such thing like AAA congruence

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Nirmla Singhal says

Please also mention the solution of question 8.

Satakshi says

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Pranav says

There is no property like AAA.

Pranav says

There is no property like AAA.

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G. K. Pal says

There is no such thing as AAA congruency

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Garima jain says

There is no AAA congruence criteria and the lengths may be different and that’s why there is no AAA congruence criteria.

Jatin says

AAA (such a criteria is not formed)

Karan says

Please tell the answer of Q8 in this exercise

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Hema Chouhan says

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Hema Chouhan says

AAA corolly is a part of Congruence