## NCERT Solutions For Class 6 Maths Practical Geometry Exercise 14.2

**NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry Ex 14.2**

**Exercise 14.2**

Ex 14.2 Class 6 Maths Question 1.

Draw a line segment of length 7.3 cm using ruler.

Solution:

Step I: Mark at point P.

Step II : Place the O mark of the ruler against the point P.

Step III : Mark a point Q at a distance of 7.3 cm from P.

Step IV : Join P and Q.

Thus is the line segment of length 7.3 cm.

Ex 14.2 Class 6 Maths Question 2.

Construct a line segment of length 5.6 cm using ruler and compass.

Solution:

Step I: Draw any line L of suitable lengths.

Step II : Place the needle of the compass on the zero mark of the ruler and open it upto 5.6 mark.

Step III : Place the needle at any point A at the line and draw an arc to cut l at B.

Thus, is the required line segment of length 5.6 cm.

Ex 14.2 Class 6 Maths Question 3.

Construct of length 7.8 cm. From this, cut off of length 4.7 cm. Measure .

Solution:

Given that = 7.8 cm and = 4.7 cm.

Step I : Place zero mark of the ruler at A.

Step II : Mark a point B at a distance of 7.8 cm from A.

Step III : Mark another point C at a distance of 4.7 cm from A such that AC = 4.7 cm.

Step IV : On measuring the length of BC, we find that = 3.1 cm.

Ex 14.2 Class 6 Maths Question 4.

Given of length 3.9 cm. Construct such that the length of is twice that of . Verify by measurement.

(Hint : Construct such that the length of = length of then cut off such that also has the length of .

Solution:

Step I: Draw a line l of suitable length.

Step II: Draw = 3.9 cm

Step III: From the line, construct = = 3.9 cm.

Step IV: Again construct = =3.9 cm

Verification: + = +

Thus twice of is equal to

Ex 14.2 Class 6 Maths Question 5.

Given of length 7.3 cm and of length 3.4 cm, construct a line segment such that the length of XY is equal to the difference between the length of and . Verify the measurement.

Solution:

Step I : Construct = 7.3 cm and = 3.4 cm.

Step II: Take a point P on the given line l.

Step III: Construct such that = = = 7.3 cm.

Step IV:Construct = = 3.4 cm such that PQ = – .

Verification : On measuring, we observe that = 3.9 cm = 7.3 cm 3.4 cm.

= –

Thus, = – .

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