NCERT Solutions For Class 6 Maths Practical Geometry Exercise 14.2
NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry Ex 14.2
Draw a line segment of length 7.3 cm using ruler.
Step I: Mark at point P.
Step II : Place the O mark of the ruler against the point P.
Step III : Mark a point Q at a distance of 7.3 cm from P.
Step IV : Join P and Q.
Thus is the line segment of length 7.3 cm.
Construct a line segment of length 5.6 cm using ruler and compass.
Step I: Draw any line L of suitable lengths.
Step II : Place the needle of the compass on the zero mark of the ruler and open it upto 5.6 mark.
Step III : Place the needle at any point A at the line and draw an arc to cut l at B.
Thus, is the required line segment of length 5.6 cm.
Construct of length 7.8 cm. From this, cut off of length 4.7 cm. Measure .
Given that = 7.8 cm and = 4.7 cm.
Step I : Place zero mark of the ruler at A.
Step II : Mark a point B at a distance of 7.8 cm from A.
Step III : Mark another point C at a distance of 4.7 cm from A such that AC = 4.7 cm.
Step IV : On measuring the length of BC, we find that = 3.1 cm.
Given of length 3.9 cm. Construct such that the length of is twice that of . Verify by measurement.
(Hint : Construct such that the length of = length of then cut off such that also has the length of .
Step I: Draw a line l of suitable length.
Step II: Draw = 3.9 cm
Step III: From the line, construct = = 3.9 cm.
Step IV: Again construct = =3.9 cm
Verification: + = +
Thus twice of is equal to
Given of length 7.3 cm and of length 3.4 cm, construct a line segment such that the length of XY is equal to the difference between the length of and . Verify the measurement.
Step I : Construct = 7.3 cm and = 3.4 cm.
Step II: Take a point P on the given line l.
Step III: Construct such that = = = 7.3 cm.
Step IV:Construct = = 3.4 cm such that PQ = – .
Verification : On measuring, we observe that = 3.9 cm = 7.3 cm 3.4 cm.
Thus, = – .