## NCERT Solutions For Class 6 Maths Fractions Exercise 7.6

Free download NCERT Solutions for Class 6 Maths Chapter 7 Ex 7.6 Fractions PDF for CBSE 2020 Exams.

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- Fractions Class 6 Ex 7.1
- Fractions Class 6 Ex 7.2
- Fractions Class 6 Ex 7.3
- Fractions Class 6 Ex 7.4
- Fractions Class 6 Ex 7.5
- Fractions Class 6 Ex 7.6

**NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6**

**Exercise 7.6**

Question 1.

Solve

Solution:

Question 2.

Sarita bought \(\frac { 2 }{ 5 }\) metre of ribbon and Lalita \(\frac { 3 }{ 4 }\) metre of ribbon. What is the total length of the ribbon they bought?

Solution:

Length of ribbon bought by Sarita = \(\frac { 2 }{ 5 }\) metre

Length of ribbon bought by Lalita = \(\frac { 3 }{ 4 }\) metre

∴ Length of ribbon bought by Sarita and Lalita

Hence, the required length = \(\frac { 23 }{ 20 }\) metre

Question 3.

Naina was given 1\(\frac { 1 }{ 2 }\) piece of cake and Najma was given 1\(\frac { 1 }{ 3 }\) piece of cake. Find the total amount of cake was given to both of them.

Solution:

Piece of cake given to Naina = 1\(\frac 1{ 1 }{ 2 }\)

Piece of cake given to Najma = 1\(\frac 1{ 1 }{ 3 }\)

Piece of cake given to Naina and Najma

Hence the total amount of piece given to both = 2\(\frac { 5 }{ 6 }\).

Question 4.

Fill in the boxes:

Solution:

Here, missing number is \(\frac { 1 }{ 4 }\) more than \(\frac { 5 }{ 8 }\) .

Here, missing number is \(\frac { 1 }{ 2 }\) more than \(\frac { 1 }{ 5 }\) .

Here, missing number is \(\frac { 1 }{ 6 }\) less than \(\frac { 1 }{ 2 }\).

Question 5.

Complete the addition-subtraction box.

Solution:

Thus the box may be completed as follows:

Question 6.

A piece of wire \(\frac { 7 }{ 8 }\) metre long broke into two pieces. One piece was \(\frac { 1 }{ 4 }\) metre long. How long is the other piece?

Solution:

Total length of the wire = \(\frac { 7 }{ 8 }\) metre

Length of one piece of wire = \(\frac { 1 }{ 4 }\) metre

∴ Length of the other piece = \(\frac { 7 }{ 8 }\) – \(\frac { 1 }{ 4 }\)

LCM of 8 and 4 = 8

Hence, the length of the other piece = \(\frac { 5 }{ 8 }\) metre.

Question 7.

Nandini’s house is \(\frac { 9 }{ 10 }\) km from her school. She walked some distance and then took a bus for \(\frac { 1 }{ 2 }\)km to reach the school. How far did she walk?

Solution:

Total distance from house to school = \(\frac { 9 }{ 10 }\) km.

Distance travelled by Nandini by bus = \(\frac { 1 }{ 2 }\) km

∴ Distance travelled by her on foot

Hence, the distance travelled by her on foot = \(\frac { 2 }{ 5 }\)km.

Question 8.

Asha and Samuel have bookshelves of the same size partly filled with books. Asha’s shelf is \(\frac { 5 }{ 6 }\) th full and Samuel’s shelf is \(\frac { 2 }{ 5 }\) th full. Whose bookshelf is more full? By what fraction?

Solution:

Asha’s shelf is \(\frac { 5 }{ 6 }\) th full

and Samuel’s shelf is \(\frac { 2 }{ 5 }\) th full

Comparing \(\frac { 5 }{ 6 }\) and \(\frac { 2 }{ 5 }\)

LCM of 6 and 5 = 30

Hence, Asha’s shelf is full more than Samuel’s shelf.

Hence, \(\frac { 13 }{ 30 }\) th fraction is more full of Asha’s shelf.

Question 9.

Jaidev takes 2\(\frac { 1 }{ 5 }\) minutes to walk across the school ground. Rahul takes \(\frac { 7 }{ 4 }\) minutes to do the same. Who takes less time and by what fraction?

Solution:

Jaidev takes 2\(\frac { 1 }{ 5 }\) minutes 5

Rahul takes 2\(\frac { 7 }{ 4 }\) minutes

Comparing 2\(\frac { 1 }{ 5 }\) minutes and \(\frac { 7 }{ 4 }\) minutes

So, the time take to cover the same distance by Rahul is less than that of Jaidev.

Hence, Rahul takes \(\frac { 9 }{ 20 }\) minutes less to across the school ground.

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