## NCERT Solutions For Class 6 Maths Fractions Exercise 7.4

Free download NCERT Solutions for Class 6 Maths Chapter 7 Ex 7.4 Fractions PDF for CBSE 2020 Exams.

You can also Download __NCERT Solutions for Class 6 Maths__ to help you to revise complete Syllabus and score more marks in your examinations.

- Fractions Class 6 Ex 7.1
- Fractions Class 6 Ex 7.2
- Fractions Class 6 Ex 7.3
- Fractions Class 6 Ex 7.4
- Fractions Class 6 Ex 7.5
- Fractions Class 6 Ex 7.6

**NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4**

**Exercise 7.4**

Question 1.

Write shaded portion as fraction. Arrange them in ascending and descending order using correct sign ‘<‘, ‘=’, ‘>’ between the fractions.

(c) Show \(\frac { 2 }{ 4 }\) , \(\frac { 4 }{ 6 }\) , \(\frac { 8 }{ 6 }\) and \(\frac { 6 }{ 6 }\) on the number line. Put appropriate signs between the fractions given.

Solution:

(a) Total number of divisions = 8

(i) Number of shaded parts = 3

∴ Fraction = \(\frac { 3 }{ 8 }\)

(ii) Total number of divisions = 8

Number of shaded parts = 6

∴ Fraction = \(\frac { 6 }{ 8 }\)

(iii) Total number of divisions = 8

Number of shaded parts = 4

∴ Fraction = \(\frac { 4 }{ 8 }\)

(iv) Total number of divisions = 8

Number of shaded part = 1

∴ Fraction = \(\frac { 1 }{ 8 }\)

Now the fractions are:

\(\frac { 3 }{ 8 }\), \(\frac { 6 }{ 8 }\), \(\frac { 4 }{ 8 }\) and \(\frac { 1 }{ 8 }\) with same denominator.

(b)(i) Total number of divisions = 9

Number of shaded parts = 8

∴ Fraction = \(\frac { 8 }{ 9 }\)

(ii) Total number of divisions = 9

Number of shaded parts = 4

∴ Fraction = \(\frac { 4 }{ 9 }\)

(iii) Total number of divisions = 9

Number of shaded parts = 3

∴ Fraction = \(\frac { 3 }{ 9 }\)

(iv) Total number of divisions = 9

Number of shaded parts = 6

∴ Fraction = \(\frac { 6 }{ 9 }\)

∴ Fractions are \(\frac { 8 }{ 9 }\), \(\frac { 4 }{ 9 }\), \(\frac { 3 }{ 9 }\), \(\frac { 6 }{ 9 }\) with same denominator.

Question 2.

Compare the fractions and put an appropriate sign.

Solution:

Here, denominators of the two fractions are same and 3 < 5.

Here, numerators of the fractions are same and 7 > 4.

Here, denominators of the two fractions are same and 4 < 5.

Here, numerators of the two fractions are same and 5 < 7.

Question 3.

Make five more such pairs and put appropriate signs.

Solution:

Question 4.

Look at the figures and write ’<’, or ’>’ ’=’ between the given pairs of fractions.

Make five more such problems and solve them with your friends

Solution:

Make five more such problems yourself and solve them with your friends.

Question 5.

How quickly can you do this? Fill appropriate sign. ‘<‘, ‘=’, ‘>’.

Solution:

Question 6.

The following fractions represent just three different numbers. Separate them into three groups of equivalent fractions, by changing each one to its simplest form.

Solution:

Now grouping the above fractions into equivalent fractions, we have

Question 7.

Find answers to the following. Write and indicate how you solved them.

Solution:

By cross-multiplying, we get

5 x 5 = 25 and 4 x 9 = 36

Since 25 ≠ 36

By cross-multiplying, we get

9 x 9 = 81 and 16 x 5 =80

Since 81 ≠ 80

By cross-multiplying, we get

4 x 20 = 80 and 5 x 16 = 80

Since 80 = 80

By cross-multiplying, we get

1 x 30 = 30 and 4 x 15 = 60

Question 8.

Ila read 25 pages of a book containing 100 pages.

Lalita read \(\frac { 2 }{ 5 }\) of the same book. Who read less?

Solution:

Ila reads 25 pages out of 100 pages.

Lalita reads \(\frac { 2 }{ 5 }\) of the same book.

Comparing \(\frac { 1 }{ 4 }\) and \(\frac { 2 }{ 5 }\) , we get

1 x 5 = 5 and 2 x 4 = 8

Since 5 < 8

∴ \(\frac { 1 }{ 4 }\) < \(\frac { 2 }{ 5 }\)

Hence Ila reads less pages.

Question 9.

Rafiq exercised for \(\frac { 3 }{ 6 }\) of an hour, while Rohit exercised for \(\frac { 3 }{ 4 }\) of an hour. Who exercised for a longer time?

Solution:

Rafiq exercised for \(\frac { 3 }{ 6 }\) of an hour.

Rohit exercised for \(\frac { 3 }{ 4 }\) of an hour.

Comparing \(\frac { 3 }{ 6 }\) and \(\frac { 3 }{ 4 }\) , we get

3 x 4 = 12 and 3 x 6 = 18

Since 12 < 18

∴ \(\frac { 3 }{ 4 }\) > \(\frac { 3 }{ 6 }\)

Hence Rohit exercised for longer time.

Question 10.

In a class A of 25 students, 20 passed in first class, in another class B of 30 students, 24 passed in first class. In which class was a greater fraction of students getting first class?

Solution:

In class A, 20 students passed in first class out of 25 students.

∴ Fraction of students getting first class

In class B, 24 students passed in first class out of 30 students.

∴ Fraction of students getting first class

Comparing the two fractions, we get \(\frac { 4 }{ 5 }\) = \(\frac { 4 }{ 5 }\)

Hence, both the class A and B have the same fractions.

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