NCERT Solutions For Class 6 Maths Fractions Exercise 7.3
Free download NCERT Solutions for Class 6 Maths Chapter 7 Ex 7.3 Fractions PDF for CBSE 2020 Exams.
You can also Download NCERT Solutions for Class 6 Maths to help you to revise complete Syllabus and score more marks in your examinations.
- Fractions Class 6 Ex 7.1
- Fractions Class 6 Ex 7.2
- Fractions Class 6 Ex 7.3
- Fractions Class 6 Ex 7.4
- Fractions Class 6 Ex 7.5
- Fractions Class 6 Ex 7.6
NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3
Exercise 7.3
Question 1.
Write the fractions. Are all these fractions equivalent?
Solution:
Since all the fractions in their simplest form are not equal.
∴ They are not equivalent fractions.
Question 2.
Write the fractions and pair up the equivalent fractions from each row.
Solution:
The following pairs fractions:represent the equivalent fractions.
(a) and (ii) = \(\frac { 1 }{ 2 }\)
(b) and (iv) = \(\frac { 2 }{ 3 }\)
(c) and (i) = \(\frac { 1 }{ 3 }\)
(d) and (v) = \(\frac { 1 }{ 4 }\)
(e) and (iii) = \(\frac { 3 }{ 4 }\)
Question 3.
Replace 
in each of the following by the correct number:
Solution:
Question 4.
Find the equivalent fraction of \(\frac { 3 }{ 5 }\) having
(a) denominator 20
(b) numerator 9
(c) denominator 30
(d) numerator 27
Solution:
(a) Here, we require denominator 20.
Let N be the numerator of the fractions.
∴ The required fraction is \(\frac { 12 }{ 20 }\)
(b) Here, we required numerator 9.
Let D be the denominator of the fraction.
∴ The required fraction is \(\frac { 9 }{ 15 }\).
(c) Here, we required denominator 30.
Let N be the numerator of the fraction.
∴ The required fraction is \(\frac { 18 }{ 30 }\).
(d) Here, we required numerator 27.
Let D be the denominator of the fraction.
∴ The required fraction is \(\frac { 27 }{ 45 }\).
Question 5.
Find the equivalent fraction of \(\frac { 36 }{ 48 }\) with
(a) numerator 9
(b) denominator 4
Solution:
(a) Given that numerator = 9
So, the equivalent fraction is \(\frac { 9 }{ 12 }\).
(b) Given that denominator = 4
∴ \(\frac { N }{ 4 }\) = \(\frac { 36 }{ 48 }\) ⇒ N x 48 = 4 x 36
⇒ N = \(\frac { 4 x 36 }{ 48 }\) = 3
So, the equivalent fraction is \(\frac { 3 }{ 4 }\) .
Question 6.
Check whether the given fractions are equivalent:
Solution:
(a) \(\frac { 5 }{ 9 }\) and \(\frac { 30 }{ 54 }\)
We have 5 x 54 = 270
and 9 x 30 = 270
Here 5 x 54 = 9 x 30
∴ \(\frac { 5 }{ 9 }\) and \(\frac { 30 }{ 54 }\) are equivalent fractions.
(b) \(\frac { 3 }{ 10 }\) and \(\frac { 12 }{ 50 }\)
We have 3 x 50 = 150
and 10 x 12 = 120
Here 3 x 50 ≠ 10 x 12
∴ \(\frac { 3 }{ 10 }\) and \(\frac { 12 }{ 50 }\) are not equivalent fractions.
(c) \(\frac { 7 }{ 13 }\) and \(\frac { 5 }{ 11 }\)
We have 7 x 11 = 77 and 5 x 13 = 65
Here 7 x 11 ≠ 5 x 13
∴ \(\frac { 7 }{ 13 }\) and \(\frac { 5 }{ 11 }\) are not equivalent fractions.
Question 7.
Reduce the following fractions to simplest form:
Solution:
Question 8.
Ramesh had 28 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up 40 pencils. What fraction did each use up? Check if each has used up an equal fraction of her/his pencils.
Solution:
Ramesh used up 10 pencils out of 20 pencils.
Sheelu used up 25 pencils out of 50 pencils.
Jamaal used up 40 pencils out of 80 pencils.
Yes, each has used up an equal fractions, i.e., \(\frac { 1 }{ 2 }\).
Question 9.
Match the equivalent fractions and write two more for each.
Solution:
Two additional examples of equivalent fractions are
Two additional examples of equivalent fractions are
Two additional examples of equivalent fractions are
Two additional examples of equivalent fractions are
Two additional examples of equivalent fractions are
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