## NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5

Get Free NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 PDF in Hindi and English Medium. Sets Class 12 Maths NCERT Solutions are extremely helpful while doing your homework. Continuity and Differentiability Exercise 5.5 Class 12 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 5 Class 12 Continuity and Differentiability Ex 5.5 provided in NCERT Textbook.

Free download NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 PDF in Hindi Medium as well as in English Medium for CBSE, Uttarakhand, Bihar, MP Board, Gujarat Board, BIE, Intermediate and UP Board students, who are using NCERT Books based on updated CBSE Syllabus for the session 2019-20.

**The topics and sub-topics included in the Continuity and Differentiability chapter are the following:**

- Continuity and Differentiability
- Introduction
- Algebra of continuous functions
- Differentiability
- Derivatives of composite functions
- Derivatives of implicit functions
- Derivatives of inverse trigonometric functions
- Exponential and Logarithmic Functions
- Logarithmic Differentiation
- Derivatives of Functions in Parametric Forms
- Second Order Derivative
- Mean Value Theorem
- Summary

There are total eight exercises and one misc exercise(**144 Questions fully solved**) in the class 12th maths chapter 5 Continuity and Differentiability.

### NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5

**Differentiate the functions given in Questions 1 to 11 w.r.to x**

**Ex 5.5 Class 12 Maths Question 1.**

cos x. cos 2x. cos 3x

**Solution:**

Let y = cos x. cos 2x . cos 3x,

Taking log on both sides,

log y = log (cos x. cos 2x. cos 3x)

log y = log cos x + log cos 2x + log cos 3x,

Differentiating w.r.t. x, we get

**Ex 5.5 Class 12 Maths Question 2.**

**Solution:**

taking log on both sides

log y = log

**Ex 5.5 Class 12 Maths Question 3.**

(log x)^{cosx}

**Solution:**

let y = (log x)^{cosx}

Taking log on both sides,

log y = log (log x)^{cosx}

log y = cos x log (log x),

Differentiating w.r.t. x,

**Ex 5.5 Class 12 Maths Question 4.**

x – 2^{sinx}

**Solution:**

let y = x – 2^{sinx},

y = u – v

**Ex 5.5 Class 12 Maths Question 5.**

(x+3)^{2}.(x + 4)^{3}.(x + 5)^{4}

**Solution:**

let y = (x + 3)^{2}.(x + 4)^{3}.(x + 5)^{4}

Taking log on both side,

logy = log [(x + 3)^{2} • (x + 4)^{3} • (x + 5)^{4}]

= log (x + 3)^{2} + log (x + 4)^{3} + log (x + 5)^{4}

log y = 2 log (x + 3) + 3 log (x + 4) + 4 log (x + 5)

Differentiating w.r.t. x, we get

**Ex 5.5 Class 12 Maths Question 6.**

**Solution:**

let

let

**Ex 5.5 Class 12 Maths Question 7.**

(log x)^{x} + x^{logx}

**Solution:**

let y = (log x)^{x} + x^{logx} = u+v

where u = (log x)^{x}

∴ log u = x log(log x)

**Ex 5.5 Class 12 Maths Question 8.**

(sin x)^{x}+sin^{-1} √x

**Solution:**

Let y = (sin x)^{x }+ sin^{-1 }√x

let u = (sin x)x, v = sin^{-1} √x

**Ex 5.5 Class 12 Maths Question 9.**

x^{sinx} + (sin x)^{cosx}

**Solution:**

let y = x^{sinx} + (sin x)^{cosx} = u+v

where u = x^{sinx}

log u = sin x log x

**Ex 5.5 Class 12 Maths Question 10.**

**Solution:**

y = u + v

**Ex 5.5 Class 12 Maths Question 11.**

**Solution:**

Let u = (x cosx)^{x}

logu = x log(x cosx)

**Find of the functions given in Questions 12 to 15.**

**Ex 5.5 Class 12 Maths Question 12.**

x^{y} + y^{x} = 1

**Solution:**

x^{y} + y^{x} = 1

let u = x^{y} and v = y^{x}

∴ u + v = 1,

Now u = x

**Ex 5.5 Class 12 Maths Question 13.**

y^{x }= x^{y}

**Solution:**

y = x

x logy = y logx

**Ex 5.5 Class 12 Maths Question 14.**

(cos x)^{y} = (cos y)^{x}

**Solution:**

We have

(cos x)^{y} = (cos y)^{x}

=> y log (cosx) = x log (cosy)

**Ex 5.5 Class 12 Maths Question 15.**

xy = e^{(x-y)}

**Solution:**

log(xy) = log e^{(x-y)}

=> log(xy) = x – y

=> logx + logy = x – y

**Ex 5.5 Class 12 Maths Question 16.**

Find the derivative of the function given by f (x) = (1 + x) (1 + x^{2}) (1 + x^{4}) (1 + x^{8}) and hence find f'(1).

**Solution:**

Let f(x) = y = (1 + x)(1 + x^{2})(1 + x^{4})(1 + x^{8})

Taking log both sides, we get

logy = log [(1 + x)(1 + x^{2})(1 + x^{4})(1 + x^{8})]

logy = log(1 + x) + log (1 + x^{2}) + log(1 + x^{4}) + log(1 + x^{8})

**Ex 5.5 Class 12 Maths Question 17.**

Differentiate (x^{2} – 5x + 8) (x^{3} + 7x + 9) in three ways mentioned below:

(i) by using product rule

(ii) by expanding the product to obtain a single polynomial.

(iii) by logarithmic differentiation.

Do they all give the same answer?

**Solution:**

(i) By using product rule

f’ = (x^{2} – 5x + 8) (3x^{2} + 7) + (x^{3} + 7x + 9) (2x – 5)

f = 5x^{4} – 20x^{3} + 45x^{2} – 52x + 11.

(ii) By expanding the product to obtain a single polynomial, we get

**Ex 5.5 Class 12 Maths Question 18.**

If u, v and w are functions of w then show that

in two ways-first by repeated application of product rule, second by logarithmic differentiation.

**Solution:**

Let y = u.v.w

=> y = u. (vw)

### NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Hindi Medium Ex 5.5

### NCERT Class 12 Maths Solutions

**Chapter 1 Relations and Functions****Chapter 2 Inverse Trigonometric Functions****Chapter 3 Matrices****Chapter 4 Determinants****Chapter 5 Continuity and Differentiability****Chapter 6 Application of Derivatives****Chapter 7 Integrals Ex 7.1****Chapter 8 Application of Integrals****Chapter 9 Differential Equations****Chapter 10 Vector Algebra****Chapter 11 Three Dimensional Geometry****Chapter 12 Linear Programming****Chapter 13 Probability Ex 13.1**