{"id":95423,"date":"2019-10-04T11:18:12","date_gmt":"2019-10-04T05:48:12","guid":{"rendered":"https:\/\/www.learncbse.in\/?p=95423"},"modified":"2020-10-20T15:35:36","modified_gmt":"2020-10-20T10:05:36","slug":"ncert-solutions-for-class-8-maths-chapter-11-mensuration-ex-11-4","status":"publish","type":"post","link":"https:\/\/www.learncbse.in\/ncert-solutions-for-class-8-maths-chapter-11-mensuration-ex-11-4\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4"},"content":{"rendered":"
NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Exercise 11.4<\/strong><\/p>\n Ex 11.4 Class 8 Maths Question 1. Ex 11.4 Class 8 Maths\u00a0Question 2. Ex 11.4 Class 8 Maths\u00a0Question 3. Ex 11.4 Class 8 Maths\u00a0Question 4. Ex 11.4 Class 8 Maths\u00a0Question 5. Ex 11.4 Class 8 Maths\u00a0Question 6. Ex 11.4 Class 8 Maths\u00a0Question 7. (ii) Original volume of the cube = x3<\/sup> cm3<\/sup> Ex 11.4 Class 8 Maths\u00a0Question 8. <\/p>\n <\/p>\n <\/p>\n <\/p>\n <\/p>\n NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 Class 8 Maths Mensuration Exercise 11.1 Class 8 Maths Mensuration Exercise 11.2 Class 8 Maths Mensuration Exercise 11.3 Class 8 Maths Mensuration Exercise 11.4 Mensuration Class 8 Extra Questions NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Exercise 11.4 Ex 11.4 Class 8 […]<\/p>\n","protected":false},"author":27,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_genesis_hide_title":false,"_genesis_hide_breadcrumbs":false,"_genesis_hide_singular_image":false,"_genesis_hide_footer_widgets":false,"_genesis_custom_body_class":"","_genesis_custom_post_class":"","_genesis_layout":""},"categories":[2],"tags":[],"yoast_head":"\n
\nGiven a cylindrical tank, in which situation will you find the surface area and in which situation volume.
\n
\n(a) To find how much it can hold.
\n(b) Number of cement bags required to plaster it.
\n(c) To find the number of smaller tanks that can be filled with water from it.
\nSolution:
\n(a) In this situation, we can find the volume.
\n(b) In this situation, we can find the surface area.
\n(c) In this situation, we can find the volume.<\/p>\n
\nDiameter of cylinder A is 7 cm, and the height is 14 cm. Diameter of cylinder B is 14 cm and height is 7 cm. Without doing any calculations can you suggest whose volume is greater? Verify it by finding the volume of both the cylinders. Check whether the cylinder with greater volume also has greater surface area?
\n
\nSolution:
\nCylinder B has a greater volume.
\nVerification:
\nVolume of cylinder A = \u03c0r2<\/sup>h
\n<\/p>\n
\nFind the height of a cuboid whose base area is 180 cm2<\/sup> and volume is 900 cm3<\/sup>.
\nSolution:
\nGiven: Area of base = lb = 180 cm2<\/sup>
\nV = 900 cm3<\/sup>
\nVolume of the cuboid = l \u00d7 b \u00d7 h
\n900 = 180 \u00d7 h
\nh = 5 cm
\nHence, the required height = 5 cm.<\/p>\n
\nA cuboid is of dimensions 60 cm \u00d7 54 cm \u00d7 30 cm. How many small cubes with side 6 cm can be placed in the given cuboid?
\nSolution:
\nVolume of the cuboid = l \u00d7 b \u00d7 h = 60 cm \u00d7 54 cm \u00d7 30 cm = 97200 cm3<\/sup>
\nVolume of the cube = (Side)3<\/sup> = (6)3<\/sup> = 216 cm3<\/sup>
\nNumber of the cubes from the cuboid
\n
\nHence, the required number of cubes = 450.<\/p>\n
\nFind the height of the cylinder whose volume is 1.54 m3<\/sup> and the diameter of the base is 140 cm.
\nSolution:
\nV = 1.54 m3<\/sup>, d = 140 cm = 1.40 m
\nVolume of the cylinder = \u03c0r2h
\n
\nHence, the height of cylinder = 1 m.<\/p>\n
\nA milk tank is in the form of a cylinder whose radius is 1.5 m and length is 7 m. Find the quantity of milk in litres that can be stored in the tank.
\n
\nSolution:
\nHere, r = 1.5 m
\nh = 7 m
\n.’. Volume of the milk tank = \u03c0r2<\/sup>h
\n= \\(\\frac { 22 }{ 7 }\\) \u00d7 1.5 \u00d7 1.5 \u00d7 7
\n= 22 \u00d7 2.25
\n= 49.50 m3<\/sup>
\nVolume of milk in litres = 49.50 \u00d7 1000 L (\u2235 1 m3<\/sup> = 1000 litres)
\n= 49500 L
\nHence, the required volume = 49500 L.<\/p>\n
\nIf each edge of a cube is doubled,
\n(i) how many times will it be surface area increase?
\n(ii) how many times will its volume increase?
\nSolution:
\nLet the edge of the cube = x cm
\nIf the edge is doubled, then the new edge = 2x cm
\n(i) Original surface area = 6x2<\/sup> cm2<\/sup>
\nNew surface area = 6(2x)2<\/sup> = 6 \u00d7 4x2<\/sup> = 24x2<\/sup>
\nRatio = 6x2<\/sup> : 24x2<\/sup> = 1 : 4
\nHence, the new surface area will be four times the original surface area.<\/p>\n
\nNew volume of the cube = (2x)3<\/sup> = 8x3<\/sup> cm3<\/sup>
\nRatio = x3<\/sup> : 8x3<\/sup> = 1 : 8
\nHence, the new volume will be eight times the original volume.<\/p>\n
\nWater is pouring into a cuboidal reservoir at the rate of 60 litres per minute. If the volume of the reservoir is 108 m3<\/sup>, find the number of hours it will take to fill the reservoir.
\nSolution:
\nVolume of the reservoir = 108 m3<\/sup> = 108000 L [\u22351 m3<\/sup> = 1000 L]
\nVolume of water flowing into the reservoir in 1 minute = 60 L
\nTime taken to fill the reservoir
\n
\nHence, the required hour to fill the reservoir = 30 hours.<\/p>\nMore CBSE Class 8 Study Material<\/h4>\n
\n